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Popular Calculus >

y^'=2xe^{(2y)}

Solution

y^{^{'}} = 2 x e^{(2 y)}

Solution

y = - \frac{ln ( - 2 x ^{2} - c _{1} )}{2}

Solution steps

y^{'} (x) = 2 x e^{(2 y)}

Solve separable ODE:

y = - \frac{ln ( - 2 x ^{2} - c _{1} )}{2}

y = - \frac{ln ( - 2 x ^{2} - c _{1} )}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=2xe^{(2y)} ?
The solution for y^'=2xe^{(2y)} is y=-(ln(-2x^2-c_{1}))/2