What is the integral of 5xsqrt(8x+5) ?

The integral of 5xsqrt(8x+5) is 1/48 (12x-5)(8x+5)^{3/2}+C

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integral of 5xsqrt(8x+5)

\int 5 x 8 x + 5 d x

\frac{1}{48} (12 x - 5) (8 x + 5)^{\frac{3}{2}} + C

Solution steps

\int 5 x 8 x + 5 d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int x 8 x + 5 d x

Apply u-substitution

= 5 \cdot \int \frac{u ( u - 5 )}{64} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \frac{1}{64} \cdot \int u (u - 5) d u

Expand

u (u - 5) : u^{\frac{3}{2}} - 5 u

= 5 \cdot \frac{1}{64} \cdot \int u^{\frac{3}{2}} - 5 u d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 5 \cdot \frac{1}{64} (\int u^{\frac{3}{2}} d u - \int 5 u d u)

\int u^{\frac{3}{2}} d u = \frac{2}{5} u^{\frac{5}{2}}

\int 5 u d u = \frac{10}{3} u^{\frac{3}{2}}

= 5 \cdot \frac{1}{64} (\frac{2}{5} u^{\frac{5}{2}} - \frac{10}{3} u^{\frac{3}{2}})

Substitute back

u = 8 x + 5

= 5 \cdot \frac{1}{64} (\frac{2}{5} (8 x + 5)^{\frac{5}{2}} - \frac{10}{3} (8 x + 5)^{\frac{3}{2}})

Simplify

5 \cdot \frac{1}{64} (\frac{2}{5} (8 x + 5)^{\frac{5}{2}} - \frac{10}{3} (8 x + 5)^{\frac{3}{2}}) : \frac{1}{48} (12 x - 5) (8 x + 5)^{\frac{3}{2}}

= \frac{1}{48} (12 x - 5) (8 x + 5)^{\frac{3}{2}}

Add a constant to the solution

= \frac{1}{48} (12 x - 5) (8 x + 5)^{\frac{3}{2}} + C

What is the integral of 5xsqrt(8x+5) ?
The integral of 5xsqrt(8x+5) is 1/48 (12x-5)(8x+5)^{3/2}+C