What is the integral of (x+x^2)/(sqrt(x)) ?

The integral of (x+x^2)/(sqrt(x)) is 2/3 x^{3/2}+2/5 x^{5/2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (x+x^2)/(sqrt(x))

\int \frac{x + x ^{2}}{x} d x

\frac{2}{3} x^{\frac{3}{2}} + \frac{2}{5} x^{\frac{5}{2}} + C

Solution steps

\int \frac{x + x ^{2}}{x} d x

Expand

\frac{x + x ^{2}}{x} : \frac{x}{x} + \frac{x ^{2}}{x}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x}{x} d x + \int \frac{x ^{2}}{x} d x

\int \frac{x}{x} d x = \frac{2}{3} x^{\frac{3}{2}}

\int \frac{x ^{2}}{x} d x = \frac{2}{5} x^{\frac{5}{2}}

= \frac{2}{3} x^{\frac{3}{2}} + \frac{2}{5} x^{\frac{5}{2}}

Add a constant to the solution

= \frac{2}{3} x^{\frac{3}{2}} + \frac{2}{5} x^{\frac{5}{2}} + C

What is the integral of (x+x^2)/(sqrt(x)) ?
The integral of (x+x^2)/(sqrt(x)) is 2/3 x^{3/2}+2/5 x^{5/2}+C