What is the integral of (-3/(x+2)-4/(x+5)) ?

The integral of (-3/(x+2)-4/(x+5)) is -3ln|x+2|-4ln|x+5|+C

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integral of (-3/(x+2)-4/(x+5))

\int (- \frac{3}{x + 2} - \frac{4}{x + 5}) d x

- 3 ln ∣ x + 2 ∣ - 4 ln ∣ x + 5 ∣ + C

Solution steps

\int - \frac{3}{x + 2} - \frac{4}{x + 5} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int \frac{3}{x + 2} d x - \int \frac{4}{x + 5} d x

\int \frac{3}{x + 2} d x = 3 ln ∣ x + 2 ∣

\int \frac{4}{x + 5} d x = 4 ln ∣ x + 5 ∣

= - 3 ln ∣ x + 2 ∣ - 4 ln ∣ x + 5 ∣

Add a constant to the solution

= - 3 ln ∣ x + 2 ∣ - 4 ln ∣ x + 5 ∣ + C

What is the integral of (-3/(x+2)-4/(x+5)) ?
The integral of (-3/(x+2)-4/(x+5)) is -3ln|x+2|-4ln|x+5|+C