What is the integral of x^{10}+10^x ?

The integral of x^{10}+10^x is (x^{11})/(11)+(10^x)/(ln(10))+C

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integral of x^{10}+10^x

\int x^{10} + 1 0^{x} d x

\frac{x ^{11}}{11} + \frac{1 0 ^{x}}{ln ( 10 )} + C

Solution steps

\int x^{10} + 1 0^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{10} d x + \int 1 0^{x} d x

\int x^{10} d x = \frac{x ^{11}}{11}

\int 1 0^{x} d x = \frac{1 0 ^{x}}{ln ( 10 )}

= \frac{x ^{11}}{11} + \frac{1 0 ^{x}}{ln ( 10 )}

Add a constant to the solution

= \frac{x ^{11}}{11} + \frac{1 0 ^{x}}{ln ( 10 )} + C

What is the integral of x^{10}+10^x ?
The integral of x^{10}+10^x is (x^{11})/(11)+(10^x)/(ln(10))+C