What is the integral of (2x+5)/((x+1)^2) ?

The integral of (2x+5)/((x+1)^2) is 2ln|x+1|-3/(x+1)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (2x+5)/((x+1)^2)

\int \frac{2 x + 5}{( x + 1 ) ^{2}} d x

2 ln ∣ x + 1 ∣ - \frac{3}{x + 1} + C

Solution steps

\int \frac{2 x + 5}{( x + 1 ) ^{2}} d x

Expand

\frac{2 x + 5}{( x + 1 ) ^{2}} : \frac{2 x}{( x + 1 ) ^{2}} + \frac{5}{( x + 1 ) ^{2}}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2 x}{( x + 1 ) ^{2}} d x + \int \frac{5}{( x + 1 ) ^{2}} d x

\int \frac{2 x}{( x + 1 ) ^{2}} d x = 2 (ln ∣ x + 1 ∣ + \frac{1}{x + 1})

\int \frac{5}{( x + 1 ) ^{2}} d x = - \frac{5}{x + 1}

= 2 (ln ∣ x + 1 ∣ + \frac{1}{x + 1}) - \frac{5}{x + 1}

Simplify

2 (ln ∣ x + 1 ∣ + \frac{1}{x + 1}) - \frac{5}{x + 1} : 2 ln ∣ x + 1 ∣ - \frac{3}{x + 1}

= 2 ln ∣ x + 1 ∣ - \frac{3}{x + 1}

Add a constant to the solution

= 2 ln ∣ x + 1 ∣ - \frac{3}{x + 1} + C

What is the integral of (2x+5)/((x+1)^2) ?
The integral of (2x+5)/((x+1)^2) is 2ln|x+1|-3/(x+1)+C