What is the integral of (1-x)/(x^2+2x+2) ?

The integral of (1-x)/(x^2+2x+2) is -1/2 ln|x^2+2x+2|+2arctan(x+1)+C

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integral of (1-x)/(x^2+2x+2)

\int \frac{1 - x}{x ^{2} + 2 x + 2} d x

- \frac{1}{2} ln x^{2} + 2 x + 2 + 2 arctan (x + 1) + C

Solution steps

\int \frac{1 - x}{x ^{2} + 2 x + 2} d x

Expand

\frac{1 - x}{x ^{2} + 2 x + 2} : \frac{1}{x ^{2} + 2 x + 2} - \frac{x}{x ^{2} + 2 x + 2}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x ^{2} + 2 x + 2} d x - \int \frac{x}{x ^{2} + 2 x + 2} d x

\int \frac{1}{x ^{2} + 2 x + 2} d x = arctan (x + 1)

\int \frac{x}{x ^{2} + 2 x + 2} d x = \frac{1}{2} ln x^{2} + 2 x + 2 - arctan (x + 1)

= arctan (x + 1) - (\frac{1}{2} ln x^{2} + 2 x + 2 - arctan (x + 1))

Simplify

= - \frac{1}{2} ln x^{2} + 2 x + 2 + 2 arctan (x + 1)

Add a constant to the solution

= - \frac{1}{2} ln x^{2} + 2 x + 2 + 2 arctan (x + 1) + C

What is the integral of (1-x)/(x^2+2x+2) ?
The integral of (1-x)/(x^2+2x+2) is -1/2 ln|x^2+2x+2|+2arctan(x+1)+C