What is the integral of (x^{-2})/(x^4) ?

The integral of (x^{-2})/(x^4) is -1/(5x^5)+C

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integral of (x^{-2})/(x^4)

\int \frac{x ^{- 2}}{x ^{4}} d x

- \frac{1}{5 x ^{5}} + C

Solution steps

\int \frac{x ^{- 2}}{x ^{4}} d x

Simplify

\frac{x ^{- 2}}{x ^{4}} : \frac{1}{x ^{6}}

= \int \frac{1}{x ^{6}} d x

Apply the Power Rule

= - \frac{1}{5 x ^{5}}

Add a constant to the solution

= - \frac{1}{5 x ^{5}} + C

What is the integral of (x^{-2})/(x^4) ?
The integral of (x^{-2})/(x^4) is -1/(5x^5)+C