What is the integral of x+sqrt(1-x^2) ?

The integral of x+sqrt(1-x^2) is (x^2)/2+1/2 (arcsin(x)+1/2 sin(2arcsin(x)))+C

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integral of x+sqrt(1-x^2)

\int x + 1 - x^{2} d x

\frac{x ^{2}}{2} + \frac{1}{2} (arcsin (x) + \frac{1}{2} sin (2 arcsin (x))) + C

Solution steps

\int x + 1 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x d x + \int 1 - x^{2} d x

\int x d x = \frac{x ^{2}}{2}

\int 1 - x^{2} d x = \frac{1}{2} (arcsin (x) + \frac{1}{2} sin (2 arcsin (x)))

= \frac{x ^{2}}{2} + \frac{1}{2} (arcsin (x) + \frac{1}{2} sin (2 arcsin (x)))

Add a constant to the solution

= \frac{x ^{2}}{2} + \frac{1}{2} (arcsin (x) + \frac{1}{2} sin (2 arcsin (x))) + C

What is the integral of x+sqrt(1-x^2) ?
The integral of x+sqrt(1-x^2) is (x^2)/2+1/2 (arcsin(x)+1/2 sin(2arcsin(x)))+C