What is the integral of (1/(x^2))^2 ?

The integral of (1/(x^2))^2 is -1/(3x^3)+C

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integral of (1/(x^2))^2

\int (\frac{1}{x ^{2}})^{2} d x

- \frac{1}{3 x ^{3}} + C

Solution steps

\int (\frac{1}{x ^{2}})^{2} d x

Simplify

(\frac{1}{x ^{2}})^{2} : \frac{1}{x ^{4}}

= \int \frac{1}{x ^{4}} d x

Apply the Power Rule

= - \frac{1}{3 x ^{3}}

Add a constant to the solution

= - \frac{1}{3 x ^{3}} + C

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What is the integral of (1/(x^2))^2 ?
The integral of (1/(x^2))^2 is -1/(3x^3)+C