What is the integral of [ 2/7 (3^x)] ?

The integral of [ 2/7 (3^x)] is 2/7*(3^x)/(ln(3))+C

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integral of [ 2/7 (3^x)]

\int [\frac{2}{7} (3^{x})] d x

\frac{2}{7} \cdot \frac{3 ^{x}}{ln ( 3 )} + C

Solution steps

\int \frac{2}{7} \cdot 3^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{2}{7} \cdot \int 3^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= \frac{2}{7} \cdot \frac{3 ^{x}}{ln ( 3 )}

Add a constant to the solution

= \frac{2}{7} \cdot \frac{3 ^{x}}{ln ( 3 )} + C

\int 2 x^{2} - 3 x + 1 d x

\int e^{- (x^{2})^{2}} d (x^{2})^{2}

\int 4 x^{3} e^{- x} d x

\int \frac{1}{13 x - 7} d x

\int \frac{1}{4 - 0.9 y} d y

What is the integral of [ 2/7 (3^x)] ?
The integral of [ 2/7 (3^x)] is 2/7*(3^x)/(ln(3))+C