What is the integral of 12ycos(4x)-3sin(y) ?

The integral of 12ycos(4x)-3sin(y) is -3sin(y)x+3ysin(4x)+C

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integral of 12ycos(4x)-3sin(y)

\int 12 y cos (4 x) - 3 sin (y) d x

- 3 sin (y) x + 3 y sin (4 x) + C

Solution steps

\int 12 y cos (4 x) - 3 sin (y) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 3 sin (y) d x + \int 12 cos (4 x) y d x

\int 3 sin (y) d x = 3 sin (y) x

\int 12 cos (4 x) y d x = 3 y sin (4 x)

= - 3 sin (y) x + 3 y sin (4 x)

Add a constant to the solution

= - 3 sin (y) x + 3 y sin (4 x) + C

What is the integral of 12ycos(4x)-3sin(y) ?
The integral of 12ycos(4x)-3sin(y) is -3sin(y)x+3ysin(4x)+C