What is the integral of arsin(x) ?

The integral of arsin(x) is -arcos(x)+C

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integral of arsin(x)

\int a r sin (x) d x

- a r cos (x) + C

Solution steps

\int a r sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= a r \cdot \int sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= a r (- cos (x))

Simplify

= - a r cos (x)

Add a constant to the solution

= - a r cos (x) + C

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