What is the integral of (cos(x))/(9sin^2(x)) ?

The integral of (cos(x))/(9sin^2(x)) is -1/9 csc(x)+C

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integral of (cos(x))/(9sin^2(x))

\int \frac{cos ( x )}{9 sin ^{2} ( x )} d x

- \frac{1}{9} csc (x) + C

Solution steps

\int \frac{cos ( x )}{9 sin ^{2} ( x )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{9} \cdot \int \frac{cos ( x )}{sin ^{2} ( x )} d x

Apply u-substitution

= \frac{1}{9} \cdot \int \frac{1}{u ^{2}} d u

Apply the Power Rule

= \frac{1}{9} (- \frac{1}{u})

Substitute back

u = sin (x)

= \frac{1}{9} (- \frac{1}{sin ( x )})

Simplify

\frac{1}{9} (- \frac{1}{sin ( x )}) : - \frac{1}{9} csc (x)

= - \frac{1}{9} csc (x)

Add a constant to the solution

= - \frac{1}{9} csc (x) + C

What is the integral of (cos(x))/(9sin^2(x)) ?
The integral of (cos(x))/(9sin^2(x)) is -1/9 csc(x)+C