What is the integral of (1/(3x^2)) ?

The integral of (1/(3x^2)) is -1/(3x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (1/(3x^2))

\int (\frac{1}{3 x ^{2}}) d x

- \frac{1}{3 x} + C

Solution steps

\int \frac{1}{3 x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

= \frac{1}{3} (- \frac{1}{x})

Simplify

\frac{1}{3} (- \frac{1}{x}) : - \frac{1}{3 x}

= - \frac{1}{3 x}

Add a constant to the solution

= - \frac{1}{3 x} + C