What is the integral from 0 to pi of (2sin(x)) ?

The integral from 0 to pi of (2sin(x)) is 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to pi of (2sin(x))

\int_{0}^{π} (2 sin (x)) d x

4

Solution steps

\int_{0}^{π} 2 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 2 [- cos (x)]_{0}^{π}

Compute the boundaries:

2

= 2 \cdot 2

Simplify

= 4

What is the integral from 0 to pi of (2sin(x)) ?
The integral from 0 to pi of (2sin(x)) is 4