What is the integral from-5 to 0 of (2-sqrt(25-x^2)) ?

The integral from-5 to 0 of (2-sqrt(25-x^2)) is 10-(25pi)/4

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integral from-5 to 0 of (2-sqrt(25-x^2))

\int_{- 5}^{0} (2 - 25 - x^{2}) d x

10 - \frac{25 π}{4}

Decimal

- 9.63495 \dots

Solution steps

\int_{- 5}^{0} 2 - 25 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 5}^{0} 2 d x - \int_{- 5}^{0} 25 - x^{2} d x

\int_{- 5}^{0} 2 d x = 10

\int_{- 5}^{0} 25 - x^{2} d x = \frac{25 π}{4}

= 10 - \frac{25 π}{4}

What is the integral from-5 to 0 of (2-sqrt(25-x^2)) ?
The integral from-5 to 0 of (2-sqrt(25-x^2)) is 10-(25pi)/4