What is the derivative of f(t)=e^{4tsin(2t)} ?

The derivative of f(t)=e^{4tsin(2t)} is e^{4tsin(2t)}*4(sin(2t)+2tcos(2t))

What is the first derivative of f(t)=e^{4tsin(2t)} ?

The first derivative of f(t)=e^{4tsin(2t)} is e^{4tsin(2t)}*4(sin(2t)+2tcos(2t))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of

f (t) = e^{4 t s i n (2 t)}

e^{4 t s i n (2 t)} \cdot 4 (sin (2 t) + 2 t cos (2 t))

Solution steps

\frac{d}{d t} (e^{4 t s i n (2 t)})

Apply the chain rule:

e^{4 t s i n (2 t)} \frac{d}{d t} (4 t sin (2 t))

= e^{4 t s i n (2 t)} \frac{d}{d t} (4 t sin (2 t))

\frac{d}{d t} (4 t sin (2 t)) = 4 (sin (2 t) + 2 t cos (2 t))

= e^{4 t s i n (2 t)} \cdot 4 (sin (2 t) + 2 t cos (2 t))

What is the derivative of f(t)=e^{4tsin(2t)} ?
The derivative of f(t)=e^{4tsin(2t)} is e^{4tsin(2t)}*4(sin(2t)+2tcos(2t))
What is the first derivative of f(t)=e^{4tsin(2t)} ?
The first derivative of f(t)=e^{4tsin(2t)} is e^{4tsin(2t)}*4(sin(2t)+2tcos(2t))