integral from 1 to 5 of xln(x)

Lösung

\int_{1}^{5} x ln (x) d x

- 6 + \frac{25}{2} ln (5)

Dezimale

14.11797 \dots

Schritte zur Lösung

\int_{1}^{5} x ln (x) d x

Wende die partielle Integration an

= [\frac{1}{2} x^{2} ln (x) - \int \frac{x}{2} d x]_{1}^{5}

\int \frac{x}{2} d x = \frac{x ^{2}}{4}

= [\frac{1}{2} x^{2} ln (x) - \frac{x ^{2}}{4}]_{1}^{5}

Berechne die Grenzen:

- 6 + \frac{25}{2} ln (5)

= - 6 + \frac{25}{2} ln (5)

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