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Popular Calculus >

integral from 1 to 4 of x^2-4x+2

Solution

\int_{1}^{4} x^{2} - 4 x + 2 d x

Solution

- 3

Solution steps

\int_{1}^{4} x^{2} - 4 x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x^{2} d x - \int_{1}^{4} 4 x d x + \int_{1}^{4} 2 d x

\int_{1}^{4} x^{2} d x = 21

\int_{1}^{4} 4 x d x = 30

\int_{1}^{4} 2 d x = 6

= 21 - 30 + 6

Simplify

= - 3

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of x^2-4x+2 ?
The integral from 1 to 4 of x^2-4x+2 is -3