What is the integral from 1 to e^1 of (ln(x))/x ?

The integral from 1 to e^1 of (ln(x))/x is 1/2

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integral from 1 to e^1 of (ln(x))/x

\int_{1}^{e^{1}} \frac{ln ( x )}{x} d x

\frac{1}{2}

Decimal

0.5

Solution steps

\int_{1}^{e^{1}} \frac{ln ( x )}{x} d x

Apply u-substitution

= \int_{0}^{1} u d u

Apply the Power Rule

= [\frac{u ^{2}}{2}]_{0}^{1}

Compute the boundaries:

\frac{1}{2}

= \frac{1}{2}

What is the integral from 1 to e^1 of (ln(x))/x ?
The integral from 1 to e^1 of (ln(x))/x is 1/2