What is the integral from 2 to 10 of (x^2+1/x) ?

The integral from 2 to 10 of (x^2+1/x) is 992/3+ln(5)

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integral from 2 to 10 of (x^2+1/x)

\int_{2}^{10} (x^{2} + \frac{1}{x}) d x

\frac{992}{3} + ln (5)

Decimal

332.27610 \dots

Solution steps

\int_{2}^{10} x^{2} + \frac{1}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{10} x^{2} d x + \int_{2}^{10} \frac{1}{x} d x

\int_{2}^{10} x^{2} d x = \frac{992}{3}

\int_{2}^{10} \frac{1}{x} d x = ln (5)

= \frac{992}{3} + ln (5)

What is the integral from 2 to 10 of (x^2+1/x) ?
The integral from 2 to 10 of (x^2+1/x) is 992/3+ln(5)