What is the integral from 0 to pi/(48) of cos(8x) ?

The integral from 0 to pi/(48) of cos(8x) is 1/16

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integral from 0 to pi/(48) of cos(8x)

\int_{0}^{\frac{π}{48}} cos (8 x) d x

\frac{1}{16}

Decimal

0.0625

Solution steps

\int_{0}^{\frac{π}{48}} cos (8 x) d x

Apply u-substitution

= \int_{0}^{\frac{π}{6}} cos (u) \frac{1}{8} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \int_{0}^{\frac{π}{6}} cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{8} [sin (u)]_{0}^{\frac{π}{6}}

Compute the boundaries:

\frac{1}{2}

= \frac{1}{8} \cdot \frac{1}{2}

Simplify

= \frac{1}{16}

What is the integral from 0 to pi/(48) of cos(8x) ?
The integral from 0 to pi/(48) of cos(8x) is 1/16