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Popular Calculus >

y^'=e^y5^x

Solution

y^{^{'}} = e^{y} 5^{x}

Solution

y = - ln (- \frac{5 ^{x}}{ln ( 5 )} - c_{1})

Solution steps

y^{'} (x) = e^{y} 5^{x}

Solve separable ODE:

y = - ln (- \frac{5 ^{x}}{ln ( 5 )} - c_{1})

y = - ln (- \frac{5 ^{x}}{ln ( 5 )} - c_{1})

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Frequently Asked Questions (FAQ)

What is the solution for y^'=e^y5^x ?
The solution for y^'=e^y5^x is y=-ln(-(5^x)/(ln(5))-c_{1})