integral from 4 to 5 of (2x-7)^4

Lösung

\int_{4}^{5} (2 x - 7)^{4} d x

\frac{121}{5}

Dezimale

24.2

Schritte zur Lösung

\int_{4}^{5} (2 x - 7)^{4} d x

Wende U-Substitution an

= \int_{1}^{3} \frac{u ^{4}}{2} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{1}^{3} u^{4} d u

Wende die Potenzregel an

= \frac{1}{2} [\frac{u ^{5}}{5}]_{1}^{3}

Berechne die Grenzen:

\frac{242}{5}

= \frac{1}{2} \cdot \frac{242}{5}

Vereinfache

= \frac{121}{5}

\int_{0}^{1} (7 x^{e} + 5 e^{x}) d x

\int_{- 3}^{1} g (x) d x

\int_{0}^{1} (- x^{2} - 3 x) d x

\int_{- 5}^{5} (5 + 25 - x^{2}) d x

\int_{0}^{1 - y^{2}} c x d x