integral from-5 to 5 of (9piz+(81pi)/2)

Lösung

\int_{- 5}^{5} (9 π z + \frac{81 π}{2}) d z

405 π

Dezimale

1272.34502 \dots

Schritte zur Lösung

\int_{- 5}^{5} 9 π z + \frac{81 π}{2} d z

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 5}^{5} 9 π z d z + \int_{- 5}^{5} \frac{81 π}{2} d z

\int_{- 5}^{5} 9 π z d z = 0

\int_{- 5}^{5} \frac{81 π}{2} d z = 405 π

= 0 + 405 π

Vereinfache

= 405 π

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