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Popular Calculus >

integral from 0 to 1 of (6-9x^2)

Solution

\int_{0}^{1} (6 - 9 x^{2}) d x

Solution

3

Solution steps

\int_{0}^{1} 6 - 9 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 6 d x - \int_{0}^{1} 9 x^{2} d x

\int_{0}^{1} 6 d x = 6

\int_{0}^{1} 9 x^{2} d x = 3

= 6 - 3

Simplify

= 3

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (6-9x^2) ?
The integral from 0 to 1 of (6-9x^2) is 3