What is the integral from-e to e of xln(x^2+1) ?

The integral from-e to e of xln(x^2+1) is 0

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integral from-e to e of xln(x^2+1)

\int_{- e}^{e} x ln (x^{2} + 1) d x

0

Solution steps

\int_{- e}^{e} x ln (x^{2} + 1) d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x ln (x^{2} + 1) :

Odd

= 0

\int_{0}^{1.5} 4 arctan (x) d x

\int_{0}^{x} \frac{1}{( 1 - x ) ^{2} ( 1 - x )} d x

\int_{1}^{2} (4 - x) d x

\int_{2}^{- 2} x^{2} - 4 d x

\int_{- 32}^{32} 5 x^{4} d x

What is the integral from-e to e of xln(x^2+1) ?
The integral from-e to e of xln(x^2+1) is 0