integral from 0 to 2 of 28-(3x^2+2x+12)

Lösung

\int_{0}^{2} 28 - (3 x^{2} + 2 x + 12) d x

20

Schritte zur Lösung

\int_{0}^{2} 28 - (3 x^{2} + 2 x + 12) d x

Vereinfache

= \int_{0}^{2} - 3 x^{2} - 2 x + 16 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{2} 3 x^{2} d x - \int_{0}^{2} 2 x d x + \int_{0}^{2} 16 d x

\int_{0}^{2} 3 x^{2} d x = 8

\int_{0}^{2} 2 x d x = 4

\int_{0}^{2} 16 d x = 32

= - 8 - 4 + 32

Vereinfache

= 20

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