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Popular Calculus >

integral from 0 to 1 of 3x^2-2x+1

Solution

\int_{0}^{1} 3 x^{2} - 2 x + 1 d x

Solution

1

Solution steps

\int_{0}^{1} 3 x^{2} - 2 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 3 x^{2} d x - \int_{0}^{1} 2 x d x + \int_{0}^{1} 1 d x

\int_{0}^{1} 3 x^{2} d x = 1

\int_{0}^{1} 2 x d x = 1

\int_{0}^{1} 1 d x = 1

= 1 - 1 + 1

Simplify

= 1

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of 3x^2-2x+1 ?
The integral from 0 to 1 of 3x^2-2x+1 is 1