integral from 1 to infinity of x/(x^2+8)

Lösung

\int_{1}^{\infty} \frac{x}{x ^{2} + 8} d x

divergiert

Schritte zur Lösung

\int_{1}^{\infty} \frac{x}{x ^{2} + 8} d x

Berechne das unbestimmte Integral:

\int \frac{x}{x ^{2} + 8} d x = \frac{1}{2} ln x^{2} + 8 + C

Berechne die Grenzen:

\int_{1}^{\infty} \frac{x}{x ^{2} + 8} d x =

divergiert

= divergiert

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