integral from 0 to pi/4 of cos(x)+sin(x)

Lösung

\int_{0}^{\frac{π}{4}} cos (x) + sin (x) d x

1

Schritte zur Lösung

\int_{0}^{\frac{π}{4}} cos (x) + sin (x) d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{\frac{π}{4}} cos (x) d x + \int_{0}^{\frac{π}{4}} sin (x) d x

\int_{0}^{\frac{π}{4}} cos (x) d x = \frac{1}{2}

\int_{0}^{\frac{π}{4}} sin (x) d x = - \frac{1}{2} + 1

= \frac{1}{2} - \frac{1}{2} + 1

Vereinfache

= 1

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