integral from 0 to 4 of 2x-2

Lösung

\int_{0}^{4} 2 x - 2 d x

8

Schritte zur Lösung

\int_{0}^{4} 2 x - 2 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 2 x d x - \int_{0}^{4} 2 d x

\int_{0}^{4} 2 x d x = 16

\int_{0}^{4} 2 d x = 8

= 16 - 8

Vereinfache

= 8

\int_{0}^{0} 16 - x^{2} d x

\int_{- 1}^{0} \frac{3 x}{( 2 + x ^{2} ) ^{4}} d x

\int_{0}^{t} (y (u) - u) d u

\int_{0}^{9} π (2 x)^{2} d x

\int_{- 1}^{1} (r + 1)^{2} d r