What is the integral from 0 to 2 of sqrt(4+x) ?

The integral from 0 to 2 of sqrt(4+x) is 4sqrt(6)-16/3

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integral from 0 to 2 of sqrt(4+x)

\int_{0}^{2} 4 + x d x

46 - \frac{16}{3}

Decimal

4.46462 \dots

Solution steps

\int_{0}^{2} 4 + x d x

Apply u-substitution

= \int_{4}^{6} u d u

Apply the Power Rule

= [\frac{2}{3} u^{\frac{3}{2}}]_{4}^{6}

Compute the boundaries:

46 - \frac{16}{3}

= 46 - \frac{16}{3}

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What is the integral from 0 to 2 of sqrt(4+x) ?
The integral from 0 to 2 of sqrt(4+x) is 4sqrt(6)-16/3