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Popular Calculus >

integral from 0 to 3 of (2x^2-8)

Solution

\int_{0}^{3} (2 x^{2} - 8) d x

Solution

- 6

Solution steps

\int_{0}^{3} 2 x^{2} - 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} 2 x^{2} d x - \int_{0}^{3} 8 d x

\int_{0}^{3} 2 x^{2} d x = 18

\int_{0}^{3} 8 d x = 24

= 18 - 24

Simplify

= - 6

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 3 of (2x^2-8) ?
The integral from 0 to 3 of (2x^2-8) is -6