3x(xy-2)dx+(x^3+2y)dy=0

Lösung

3 x (x y - 2) d x + (x^{3} + 2 y) d y = 0

y = \frac{- x ^{3} + x ^{6} - 4 ( - 3 x ^{2} - c _{1} )}{2}, y = \frac{- x ^{3} - x ^{6} - 4 ( - 3 x ^{2} - c _{1} )}{2}

Schritte zur Lösung

3 x (x y - 2) d x + (x^{3} + 2 y) d y = 0

Solve exact ODE:

y = \frac{- x ^{3} + x ^{6} - 4 ( - 3 x ^{2} - c _{1} )}{2}, y = \frac{- x ^{3} - x ^{6} - 4 ( - 3 x ^{2} - c _{1} )}{2}

y = \frac{- x ^{3} + x ^{6} - 4 ( - 3 x ^{2} - c _{1} )}{2}, y = \frac{- x ^{3} - x ^{6} - 4 ( - 3 x ^{2} - c _{1} )}{2}

\frac{d}{d x} ((arcsec (\frac{x ^{2}}{2}))^{3 x})

\int e^{s i n (x)} sin (2 x) d x

x \to 5 lim (g (x))

\int \frac{1}{48} x d x

d er i v a t i v e \frac{10 x + 8 x ^{2}}{( 5 + 8 x ) ^{2}}