What is the d/(dq)((5+1)/((cot(q)))) ?

The d/(dq)((5+1)/((cot(q)))) is 6sec^2(q)

What is the first d/(dq)((5+1)/((cot(q)))) ?

The first d/(dq)((5+1)/((cot(q)))) is 6sec^2(q)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d q} (\frac{5 + 1}{( cot ( q ) )})

6 sec^{2} (q)

Solution steps

\frac{d}{d q} (\frac{5 + 1}{( cot ( q ) )})

Simplify

\frac{5 + 1}{( cot ( q ) )} : 6 tan (q)

= \frac{d}{d q} (6 tan (q))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d q} (tan (q))

Apply the common derivative:

\frac{d}{d q} (tan (q)) = sec^{2} (q)

= 6 sec^{2} (q)

What is the d/(dq)((5+1)/((cot(q)))) ?
The d/(dq)((5+1)/((cot(q)))) is 6sec^2(q)
What is the first d/(dq)((5+1)/((cot(q)))) ?
The first d/(dq)((5+1)/((cot(q)))) is 6sec^2(q)