What is the derivative of e^{2x-y+z} ?

The derivative of e^{2x-y+z} is e^{2x-y+z}*2

What is the first derivative of e^{2x-y+z} ?

The first derivative of e^{2x-y+z} is e^{2x-y+z}*2

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derivative of

e^{2 x - y + z}

e^{2 x - y + z} \cdot 2

Solution steps

\frac{d}{d x} (e^{2 x - y + z})

Treat

y, z

as constants

Apply the chain rule:

e^{2 x - y + z} \frac{d}{d x} (2 x - y + z)

= e^{2 x - y + z} \frac{d}{d x} (2 x - y + z)

\frac{d}{d x} (2 x - y + z) = 2

= e^{2 x - y + z} \cdot 2

What is the derivative of e^{2x-y+z} ?
The derivative of e^{2x-y+z} is e^{2x-y+z}*2
What is the first derivative of e^{2x-y+z} ?
The first derivative of e^{2x-y+z} is e^{2x-y+z}*2