What is the derivative of (t^2)/(20)+t/5 ?

The derivative of (t^2)/(20)+t/5 is t/(10)+1/5

What is the first derivative of (t^2)/(20)+t/5 ?

The first derivative of (t^2)/(20)+t/5 is t/(10)+1/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of

\frac{t ^{2}}{20} + \frac{t}{5}

\frac{t}{10} + \frac{1}{5}

Solution steps

\frac{d}{d t} (\frac{t ^{2}}{20} + \frac{t}{5})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (\frac{t ^{2}}{20}) + \frac{d}{d t} (\frac{t}{5})

\frac{d}{d t} (\frac{t ^{2}}{20}) = \frac{t}{10}

\frac{d}{d t} (\frac{t}{5}) = \frac{1}{5}

= \frac{t}{10} + \frac{1}{5}

What is the derivative of (t^2)/(20)+t/5 ?
The derivative of (t^2)/(20)+t/5 is t/(10)+1/5
What is the first derivative of (t^2)/(20)+t/5 ?
The first derivative of (t^2)/(20)+t/5 is t/(10)+1/5