What is the derivative of y=7x^3+2x^2+4x ?

The derivative of y=7x^3+2x^2+4x is 21x^2+4x+4

What is the first derivative of y=7x^3+2x^2+4x ?

The first derivative of y=7x^3+2x^2+4x is 21x^2+4x+4

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derivative of

y = 7 x^{3} + 2 x^{2} + 4 x

21 x^{2} + 4 x + 4

Solution steps

\frac{d}{d x} (7 x^{3} + 2 x^{2} + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (7 x^{3}) + \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (4 x)

\frac{d}{d x} (7 x^{3}) = 21 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4 x) = 4

= 21 x^{2} + 4 x + 4

d er i v a t i v e ln ((1 + 3 x)^{2})

d er i v a t i v e \frac{3}{x ^{2} + 2}

d er i v a t i v e \frac{3 x}{5}

\frac{d}{d r} (\frac{1}{2 r ( a + b + c )})

d er i v a t i v e (x + 5)^{- 1}

What is the derivative of y=7x^3+2x^2+4x ?
The derivative of y=7x^3+2x^2+4x is 21x^2+4x+4
What is the first derivative of y=7x^3+2x^2+4x ?
The first derivative of y=7x^3+2x^2+4x is 21x^2+4x+4