What is derivative of x^2+y^2=6x+4y ?

The answer to derivative of x^2+y^2=6x+4y is (dy)/(dx)=(3-x)/(-2+y)

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derivative of x^2+y^2=6x+4y

derivative of

x^{2} + y^{2} = 6 x + 4 y

\frac{d y}{d x} = \frac{3 - x}{- 2 + y}

Solution steps

x^{2} + y^{2} = 6 x + 4 y

Treat

y

y (x)

Differentiate both sides:

2 x + 2 y \frac{d y}{d x} = 6 + 4 \frac{d y}{d x}

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{3 - x}{- 2 + y}

\frac{d y}{d x} = \frac{3 - x}{- 2 + y}

What is derivative of x^2+y^2=6x+4y ?
The answer to derivative of x^2+y^2=6x+4y is (dy)/(dx)=(3-x)/(-2+y)