What is the integral of 1/((2-x)) ?

The integral of 1/((2-x)) is -ln|2-x|+C

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integral of 1/((2-x))

integral

\frac{1}{( 2 - x )}

- ln ∣ 2 - x ∣ + C

Solution steps

\int \frac{1}{2 - x} d x

Apply u-substitution

= \int - \frac{1}{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= - ln ∣ u ∣

Substitute back

u = 2 - x

= - ln ∣ 2 - x ∣

Add a constant to the solution

= - ln ∣ 2 - x ∣ + C

in t e g r a l \frac{( 1 - x ^{3} )}{( 1 - x )}

in t e g r a l \frac{1}{( 1 + lo g _{10} ( x ) )}

in t e g r a l - e^{y} - 2

in t e g r a l \frac{1}{a ^{2} + x ^{2}}

in t e g r a l lo g_{10} (x^{2} + 4)