What is the integral of x/(sqrt(x^2+y^2)) ?

The integral of x/(sqrt(x^2+y^2)) is sqrt(y^2+x^2)+C

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integral of x/(sqrt(x^2+y^2))

integral

\frac{x}{x ^{2} + y ^{2}}

y^{2} + x^{2} + C

Solution steps

\int \frac{x}{x ^{2} + y ^{2}} d x

Apply u-substitution

= \int \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{u} d u

Apply the Power Rule

= \frac{1}{2} \cdot 2 u^{\frac{1}{2}}

Substitute back

u = y^{2} + x^{2}

= \frac{1}{2} \cdot 2 (y^{2} + x^{2})^{\frac{1}{2}}

Simplify

\frac{1}{2} \cdot 2 (y^{2} + x^{2})^{\frac{1}{2}} : y^{2} + x^{2}

= y^{2} + x^{2}

Add a constant to the solution

= y^{2} + x^{2} + C

What is the integral of x/(sqrt(x^2+y^2)) ?
The integral of x/(sqrt(x^2+y^2)) is sqrt(y^2+x^2)+C