What is the integral of 2tcosh(t^2) ?

The integral of 2tcosh(t^2) is sinh(t^2)+C

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integral of 2tcosh(t^2)

integral

2 t cosh (t^{2})

sinh (t^{2}) + C

Solution steps

\int 2 t cosh (t^{2}) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int t cosh (t^{2}) d t

Apply u-substitution

= 2 \cdot \int \frac{cosh ( u )}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{2} \cdot \int cosh (u) d u

Use the common integral:

\int cosh (u) d u = sinh (u)

= 2 \cdot \frac{1}{2} sinh (u)

Substitute back

u = t^{2}

= 2 \cdot \frac{1}{2} sinh (t^{2})

Simplify

2 \cdot \frac{1}{2} sinh (t^{2}) : sinh (t^{2})

= sinh (t^{2})

Add a constant to the solution

= sinh (t^{2}) + C

What is the integral of 2tcosh(t^2) ?
The integral of 2tcosh(t^2) is sinh(t^2)+C