What is the solution for (d-1)^4y=e^x ?

The solution for (d-1)^4y=e^x is y=c_{1}e^x+c_{2}xe^x+c_{3}x^2e^x+c_{4}x^3e^x+(e^xx^4)/(24)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(d-1)^4y=e^x

(d - 1)^{4} y = e^{x}

y = c_{1} e^{x} + c_{2} x e^{x} + c_{3} x^{2} e^{x} + c_{4} x^{3} e^{x} + \frac{e ^{x} x ^{4}}{24}

Solution steps

(d - 1)^{4} y = e^{x}

Solve linear ODE:

y = c_{1} e^{x} + c_{2} x e^{x} + c_{3} x^{2} e^{x} + c_{4} x^{3} e^{x} + \frac{e ^{x} x ^{4}}{24}

y = c_{1} e^{x} + c_{2} x e^{x} + c_{3} x^{2} e^{x} + c_{4} x^{3} e^{x} + \frac{e ^{x} x ^{4}}{24}

What is the solution for (d-1)^4y=e^x ?
The solution for (d-1)^4y=e^x is y=c_{1}e^x+c_{2}xe^x+c_{3}x^2e^x+c_{4}x^3e^x+(e^xx^4)/(24)