What is the integral of (x^2sqrt(x)) ?

The integral of (x^2sqrt(x)) is 2/7 x^{7/2}+C

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integral of (x^2sqrt(x))

\int (x^{2} x) d x

\frac{2}{7} x^{\frac{7}{2}} + C

Solution steps

\int x^{2} x d x

Simplify

x^{2} x : x^{\frac{5}{2}}

= \int x^{\frac{5}{2}} d x

Apply the Power Rule

= \frac{2}{7} x^{\frac{7}{2}}

Add a constant to the solution

= \frac{2}{7} x^{\frac{7}{2}} + C

What is the integral of (x^2sqrt(x)) ?
The integral of (x^2sqrt(x)) is 2/7 x^{7/2}+C