What is the integral of 1/(x((ln(x))^2)) ?

The integral of 1/(x((ln(x))^2)) is -1/(ln(x))+C

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integral of 1/(x((ln(x))^2))

\int \frac{1}{x ( ( ln ( x ) ) ^{2} )} d x

- \frac{1}{ln ( x )} + C

Solution steps

\int \frac{1}{x ( ln ( x ) ) ^{2}} d x

Apply u-substitution

= \int \frac{1}{u ^{2}} d u

Apply the Power Rule

= - \frac{1}{u}

Substitute back

u = ln (x)

= - \frac{1}{ln ( x )}

Add a constant to the solution

= - \frac{1}{ln ( x )} + C

What is the integral of 1/(x((ln(x))^2)) ?
The integral of 1/(x((ln(x))^2)) is -1/(ln(x))+C