integral of (3-0.01x+0.00006x^2)

Lösung

\int (3 - 0.01 x + 0.00006 x^{2}) d x

3 x - 0.005 x^{2} + 0.00002 x^{3} + C

Schritte zur Lösung

\int 3 - 0.01 x + 0.00006 x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 d x - \int 0.01 x d x + \int 0.00006 x^{2} d x

\int 3 d x = 3 x

\int 0.01 x d x = 0.005 x^{2}

\int 0.00006 x^{2} d x = 0.00002 x^{3}

= 3 x - 0.005 x^{2} + 0.00002 x^{3}

Füge eine Konstante zur Lösung hinzu

= 3 x - 0.005 x^{2} + 0.00002 x^{3} + C

\int \frac{1}{( x + 2 ) x ^{2} + 4 x - 5} d x

\int 2 cos (x) (\frac{2 csc ( x )}{cot ( x )}) d x

\int \frac{1}{x ( 4 + ( 3 ln ( x ) ) ^{2} )} d x

\int \frac{e ^{x}}{1 + 2 e ^{x} + e ^{2 x}} d x

\int \frac{x - 1}{x ^{2}} d x