What is the integral of (7cosh(x)+1+tan^2(x)) ?

The integral of (7cosh(x)+1+tan^2(x)) is 7sinh(x)+tan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (7cosh(x)+1+tan^2(x))

\int (7 cosh (x) + 1 + tan^{2} (x)) d x

7 sinh (x) + tan (x) + C

Solution steps

\int 7 cosh (x) + 1 + tan^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 7 cosh (x) d x + \int 1 d x + \int tan^{2} (x) d x

\int 7 cosh (x) d x = 7 sinh (x)

\int 1 d x = x

\int tan^{2} (x) d x = - x + tan (x)

= 7 sinh (x) + x - x + tan (x)

Simplify

= 7 sinh (x) + tan (x)

Add a constant to the solution

= 7 sinh (x) + tan (x) + C

What is the integral of (7cosh(x)+1+tan^2(x)) ?
The integral of (7cosh(x)+1+tan^2(x)) is 7sinh(x)+tan(x)+C