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人気のある微分積分 >

integral from 15 to 30 of x^2sin(5)x^3

解

\int_{1 5^{\circ}}^{3 0^{\circ}} x^{2} sin (5) x^{3} d x

解

sin (5) (\frac{( 3 0 ^{\circ} ) ^{6}}{6} - \frac{( 1 5 ^{\circ} ) ^{6}}{6})

+1

十進法表記

- 0.00324 \dots

解答ステップ

\int_{1 5^{\circ}}^{3 0^{\circ}} x^{2} sin (5) x^{3} d x

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sin (5) \cdot \int_{1 5^{\circ}}^{3 0^{\circ}} x^{2} x^{3} d x

簡素化

x^{2} x^{3} : x^{5}

= sin (5) \cdot \int_{1 5^{\circ}}^{3 0^{\circ}} x^{5} d x

べき乗則を適用する

= sin (5) [\frac{x ^{6}}{6}]_{1 5^{\circ}}^{3 0^{\circ}}

限度を計算する:

\frac{( 3 0 ^{\circ} ) ^{6}}{6} - \frac{( 1 5 ^{\circ} ) ^{6}}{6}

= sin (5) (\frac{( 3 0 ^{\circ} ) ^{6}}{6} - \frac{( 1 5 ^{\circ} ) ^{6}}{6})

グラフ

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